How to Solve Maria's Strawberry Purchase Puzzle: A Detailed Guide
Maria's purchase puzzle can be a great way to apply mathematical concepts to real-life scenarios. In this guide, we'll walk through how Maria managed her money and provide a detailed solution.
Understanding the Problem
Maria spent a fifth of the money in her wallet on her first purchase. From the remaining money, she could buy 2 kg of strawberries. However, she only bought 1.5 kg of strawberries for £0.60. The question is, how much money did Maria originally have in her wallet?
Step-by-Step Solution
Identifying Key Information
Maria spent a fifth of her total money on her first purchase. With the remaining money, she could have bought 2 kg of strawberries. She actually bought 1.5 kg of strawberries for £0.60.Formulating the Problem with Algebra
Let's denote the total amount of money Maria originally had as ( M ) in pounds (£).
Calculating the Remaining Money After the First Purchase
Maria spent a fifth of her money on the first purchase. Therefore, she spent ( frac{M}{5} ) pounds.
The remaining money after this purchase is:
( text{Remaining money} M - frac{M}{5} frac{4M}{5} )
Determining the Price Per Kilogram of Strawberries
Maria bought 1.5 kg of strawberries for £0.60. To find the price per kilogram, we calculate:
( text{Price per kg} frac{0.60}{1.5} 0.40 ) pounds per kg
Calculating the Total Cost for 2 kg of Strawberries
The cost for 2 kg of strawberries at the price of £0.40 per kg would be:
( text{Cost for 2 kg} 2 times 0.40 0.80 ) pounds
Relating the Remaining Money to the Total Money
Since the remaining money after the first purchase could buy 2 kg of strawberries, we have:
( frac{4M}{5} 0.80 )
Solving for ( M ):
( 4M 0.80 times 5 )
( 4M 4 )
( M 1 )
Maria originally had £1 in her wallet.
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Conclusion
Solving Maria's strawberry purchase puzzle involves a series of logical steps and application of basic mathematical concepts. By understanding the problem and breaking it down, we can easily determine how much money Maria originally had in her wallet.