Calculation of the Mass of Sucrose in Grams from Moles

Calculation of the Mass of Sucrose in Grams from Moles

Sucrose, with the chemical formula C12H22O11, is a key sugar component found in many foods and beverages. Understanding how to convert moles to grams for sucrose is essential in various applications, including chemistry, food science, and pharmacology. This article will guide you through the process of calculating the mass of sucrose from a given number of moles, using the molar mass of sucrose.

Molar Mass of Sucrose

The molar mass of sucrose is given as 342.296 g/mol. This means that one mole of sucrose has a mass of 342.296 grams. If you have a different number of moles, you can calculate the mass by multiplying the number of moles by the molar mass.

Problem Statement

Let's consider the specific problem: What is the mass in grams of 0.105 moles of sucrose (C12H22O11)?

Solution

Given:

Number of moles of sucrose 0.105 moles Molar mass of sucrose (C12H22O11) 342 g/mol

Required: Mass of sucrose in grams.

Solution:

Mass of sucrose number of moles of sucrose × molar mass of sucrose

0.105 moles × 342 g/mol

35.91 grams

Now, rounding to three significant figures:

Mass of sucrose 35.9 grams

Calculation Steps

1. Determine the Molar Mass: The molar mass of sucrose (C12H22O11) is 342.296 g/mol. 2. Identify the Number of Moles: In this case, you have 0.105 moles of sucrose. 3. Multiply Molar Mass by Moles: Multiply the number of moles of sucrose by its molar mass.

0.105 moles × 342 g/mol 35.91 grams

Rounding to three significant figures: 35.9 grams

Additional Insights

The molar mass of sucrose (C12H22O11) can also be expressed as 342.3 g/mol for practical purposes. The formula weight of sucrose is essentially its molar mass, which is the sum of the atomic weights of all atoms in the molecule.

Thus, for 0.105 moles of sucrose, the mass is calculated as:

0.105 moles × 342.3 g/mol 35.9415 grams

Rounding to three significant figures: 35.9 grams

Or, considering the molar mass as 342.3 g/mol and the number of molecules in one mole (6.022×1023 molecules), the mass calculation remains consistent with the grams per mole ratio:

342.3 g/mol × 0.105 moles 35.9 grams

Dimensional Analysis and Consistency

The product of moles and the molar mass (in grams per mole) should yield the final answer in grams, which is the desired unit. This consistency is crucial in scientific calculations.

Key Takeaway: To find the mass of sucrose in grams from a given number of moles, simply multiply the number of moles by the molar mass of sucrose (342.3 g/mol). For 0.105 moles, this results in 35.9 grams, making the conversion straightforward and practical.